Showing posts with label AC Circuit. Show all posts
Saturday, January 31, 2015
AC Circuits: Calculating the Total Impedance Problem #1
A 100-ohm resistor, 5mH inductor, and a 10uF capacitor are connected in series to a 7V (Volts), 1kHz (kiloHertz) source. Calculate the total reactance and impedance of the circuit.
Here is how to get the total impedance, if you do not know yet.
Solution:
Z_t = R + jX_{eq}
Z_t = R + j(X_L - X_C)
Z_t = 100\Omega + j(31.42\Omega - 15.92\Omega)
Rectangular form:
Z_t = 100\Omega + j15.5\Omega
Polar form:
Z_t = 101.19\angle8.81^{\circ}\Omega
Check below for more relevant sample problems with their answers and solutions. If you have questions about the solution or answer, place a comment below.
Thursday, January 22, 2015
AC Circuits: Equivalent Reactance of a Series RLC Circuit problem #1
A 100 Ohms resistor, 5 mH inductor, and a 10 uF capacitor are connected in series to a 7V (Volts), 1kHz (kiloHertz) source. Calculate the equivalent reactance.
To calculate the equivalent reactance of the circuit in the figure below, we need to use the formulas written HERE.
Solving for the inductive reactance,
Solving for the capacitive reactance,
Note: As much as possible, don't round off the values except the final answer in order to have minimal errors. This is applicable not just with this topic but to almost any.
Now, solving for the equivalent reactance,
If you have any question, place a comment below. We will solve this circuit's impedance in another post.
Update: Solution and answer for the total impedance is here!
To calculate the equivalent reactance of the circuit in the figure below, we need to use the formulas written HERE.
X_L = 2{\pi}f{L_1}
X_L = 2{\pi}(1 kHz)(5 mH)
X_L = 2{\pi}(1000 Hz)(5x10^{-3} H)
X_L = 31.42\Omega
Solving for the capacitive reactance,
X_C = \frac{1}{2{\pi}f{C_1}}
X_C = \frac{1}{2{\pi}(1kHz)(10{\mu}F)}
X_C = \frac{1}{2{\pi}(1000 Hz)(10x10^{-6}F)}
X_C = 15.92\Omega
Note: As much as possible, don't round off the values except the final answer in order to have minimal errors. This is applicable not just with this topic but to almost any.
Now, solving for the equivalent reactance,
X_{eq} = X_L - X_C
X_{eq} = 31.42\Omega - 15.92\Omega
X_{eq} = 15.5\Omega
If you have any question, place a comment below. We will solve this circuit's impedance in another post.
Update: Solution and answer for the total impedance is here!
Subscribe to:
Posts
(
Atom
)